1. Balanced Chemical Equation:

The decomposition of potassium chlorate (KClO₃) produces potassium chloride (KCl) and oxygen gas (O₂):

2 KClO₃ → 2 KCl + 3 O₂

2. Mole Ratio:

The balanced equation shows that 2 moles of potassium chlorate (KClO₃) produce 3 moles of oxygen gas (O₂).

3. Calculation:

* You have 14 moles of potassium chlorate.

* Using the mole ratio from the balanced equation, we can set up a proportion:

(2 moles KClO₃) / (3 moles O₂) = (14 moles KClO₃) / (x moles O₂)

* Solve for x (moles of O₂):

x = (14 moles KClO₃ * 3 moles O₂) / (2 moles KClO₃)

x = 21 moles O₂

Answer: 14 moles of potassium chlorate will produce 21 moles of oxygen gas.