1. Find the empirical formula mass:

* C: 12.01 g/mol * 2 = 24.02 g/mol

* H: 1.01 g/mol * 6 = 6.06 g/mol

* O: 16.00 g/mol * 1 = 16.00 g/mol

* Total empirical formula mass = 24.02 + 6.06 + 16.00 = 46.08 g/mol

2. Determine the ratio of molecular mass to empirical formula mass:

* Ratio = 138 g/mol / 46.08 g/mol = 3

3. Multiply the subscripts in the empirical formula by the ratio:

* C2H6O * 3 = C6H18O3

Therefore, the molecular formula of the compound is C6H18O3.