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  • Copper Purification by Electrolysis: Half-Reactions Explained
    Here's a breakdown of the half-equations involved in purifying copper using electrolysis, along with an explanation:

    The Process

    Copper refining via electrolysis is a process that uses an electric current to separate impurities from impure copper (often called blister copper). Here's a simplified overview:

    1. Electrolyte: The process uses an electrolyte solution containing copper(II) sulfate (CuSO₄) and sulfuric acid (H₂SO₄).

    2. Anode: The impure copper is used as the anode (positive electrode).

    3. Cathode: A thin sheet of pure copper acts as the cathode (negative electrode).

    Half-Reactions

    * Oxidation at the Anode (Impure Copper):

    - Cu(s) → Cu²⁺(aq) + 2e⁻

    This half-reaction represents the oxidation of copper atoms at the anode. The copper atoms lose electrons to form copper(II) ions, which dissolve into the electrolyte.

    * Reduction at the Cathode (Pure Copper):

    - Cu²⁺(aq) + 2e⁻ → Cu(s)

    This half-reaction represents the reduction of copper(II) ions at the cathode. The copper(II) ions from the electrolyte gain electrons and deposit as pure copper on the cathode.

    Impurities

    * More Reactive Metals: Metals like zinc (Zn) and iron (Fe) that are more reactive than copper will also be oxidized at the anode. They will form their respective ions (Zn²⁺ and Fe²⁺) and remain in the electrolyte solution.

    * Less Reactive Metals: Metals like silver (Ag) and gold (Au) that are less reactive than copper will not be oxidized. They will fall to the bottom of the anode as a valuable "anode mud."

    Overall Reaction

    The overall reaction can be written as the sum of the two half-reactions:

    Cu(impure) → Cu(pure)

    Important Note: This is a simplified explanation. The actual process can involve complex reactions and side reactions, and the specific conditions of the electrolysis can influence the outcome.

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