1. Calculate the molar mass of MgCl₂:

* Mg: 24.31 g/mol

* Cl: 35.45 g/mol

* Molar mass of MgCl₂ = 24.31 g/mol + (2 * 35.45 g/mol) = 95.21 g/mol

2. Convert the mass of MgCl₂ to moles:

* Moles of MgCl₂ = (0.96 g) / (95.21 g/mol) = 0.0101 mol

3. Calculate the molarity:

* Molarity (M) = (moles of solute) / (liters of solution)

* Molarity = (0.0101 mol) / (0.500 L) = 0.0202 M

Therefore, the molarity of the 0.96 g MgCl₂ in 0.500 L solution is 0.0202 M.