The Reaction:
CH₃COONa (aq) + H₂O (l) ⇌ CH₃COOH (aq) + Na⁺ (aq) + OH⁻ (aq)
Explanation:
* Sodium acetate (CH₃COONa) is a salt that dissolves in water to form sodium ions (Na⁺) and acetate ions (CH₃COO⁻).
* Water (H₂O) is a weak acid and a weak base, meaning it can act as both a proton donor (acid) and a proton acceptor (base).
* Acetic acid (CH₃COOH) is formed when the acetate ion (CH₃COO⁻) reacts with a proton (H⁺) from water.
* Hydroxide ions (OH⁻) are formed as a byproduct of the reaction.
Equilibrium:
The reaction is an equilibrium reaction, meaning it doesn't go to completion in one direction. The position of the equilibrium depends on the concentration of the reactants and products.
Key Points:
* The reaction results in a slightly basic solution because hydroxide ions (OH⁻) are produced.
* The acetate ion is a weak base, which means it has a tendency to accept protons, making the solution slightly basic.
* The solution will also contain some acetic acid, as the reaction is in equilibrium.
Let me know if you have any other questions!
