B₂S₃ (s) + 6 H₂O (l) → 2 H₃BO₃ (aq) + 3 H₂S (g)
Explanation:
* Reactants:
* Boron sulfide (B₂S₃) is a solid.
* Water (H₂O) is a liquid.
* Products:
* Boric acid (H₃BO₃) is dissolved in water, forming an aqueous solution (aq).
* Hydrogen sulfide (H₂S) is a gas (g).
* Balancing:
* The equation is balanced by ensuring that the number of atoms of each element is the same on both sides of the equation.
* Two boron atoms, three sulfur atoms, and twelve hydrogen atoms appear on both sides.
Important Note: This reaction is highly exothermic and produces hydrogen sulfide gas, which is toxic. Therefore, this reaction should only be performed in a controlled laboratory setting with proper safety precautions.
