Here's how to write the molecular equation for the reaction between copper(II) sulfate and barium chloride:

1. Identify the Reactants:

* Copper(II) sulfate: CuSO₄

* Barium chloride: BaCl₂

2. Determine the Products:

This is a double displacement reaction where the cations and anions switch partners. The products will be:

* Copper(II) chloride: CuCl₂

* Barium sulfate: BaSO₄

3. Balance the Equation:

The balanced molecular equation is:

CuSO₄(aq) + BaCl₂(aq) → CuCl₂(aq) + BaSO₄(s)

Explanation:

* (aq) indicates that the substance is dissolved in water (aqueous solution).

* (s) indicates that the substance is a solid precipitate.

* The equation is balanced because there are equal numbers of each type of atom on both sides of the equation.

Key points:

* Barium sulfate (BaSO₄) is insoluble in water and will precipitate out of solution as a white solid.

* This reaction is used in laboratory settings to identify the presence of barium ions.