Here's why:
* Aluminum is a metal in group 3A (13) of the periodic table, and it typically forms a +3 charge (Al³⁺).
* Bromine is a nonmetal in group 7A (17) of the periodic table, and it typically forms a -1 charge (Br⁻).
To form a neutral compound, you need three bromine atoms (3 x -1 = -3) to balance the +3 charge of the aluminum atom. This results in the formula AlBr₃.