1. Write the balanced chemical equation:

HCl (aq) + NaOH (aq) → NaCl (aq) + H₂O (l)

2. Determine the limiting reactant:

* Moles of HCl: We need to assume you meant 1.4 moles of HCl. If you meant 1.4 g, you'd need to convert that to moles using the molar mass of HCl.

* Moles of NaOH: 2.8 moles

Since the stoichiometric ratio between HCl and NaOH is 1:1, the limiting reactant is HCl because there are fewer moles of it.

3. Calculate the moles of NaCl formed:

The stoichiometric ratio between HCl and NaCl is also 1:1. Therefore, the number of moles of NaCl formed will be equal to the number of moles of the limiting reactant (HCl).

Answer: 1.4 moles of NaCl are formed.