1. Convert grams of solute to moles:
* Find the molar mass of barium chloride (BaCl₂):
* Barium (Ba): 137.33 g/mol
* Chlorine (Cl): 35.45 g/mol (x2 for two chlorine atoms)
* Molar mass of BaCl₂ = 137.33 + (35.45 x 2) = 208.23 g/mol
* Divide the mass of barium chloride by its molar mass to find the moles:
* Moles of BaCl₂ = 35.0 g / 208.23 g/mol = 0.168 mol
2. Convert milliliters of solution to liters:
* Divide the volume in milliliters by 1000:
* Liters of solution = 450.0 ml / 1000 ml/L = 0.450 L
3. Calculate molarity:
* Molarity (M) is defined as moles of solute per liter of solution:
* Molarity = Moles of BaCl₂ / Liters of solution
* Molarity = 0.168 mol / 0.450 L
* Molarity = 0.373 M
Therefore, the molarity of the barium chloride solution is 0.373 M.
