1. Find the molar mass of AlCl₃
* Aluminum (Al) has a molar mass of 26.98 g/mol
* Chlorine (Cl) has a molar mass of 35.45 g/mol
* AlCl₃ has one aluminum atom and three chlorine atoms:
* Molar mass of AlCl₃ = (1 * 26.98 g/mol) + (3 * 35.45 g/mol) = 133.33 g/mol
2. Calculate the number of moles
* Moles = Mass / Molar Mass
* Moles = 32.5 g / 133.33 g/mol
* Moles ≈ 0.244
Therefore, there are approximately 0.244 moles of aluminum chloride in 32.5 grams.
