Here's why:

* Lead (Pb) typically forms two common oxidation states: +2 and +4.

* Iodine (I) is a halogen and typically forms an anion with a -1 charge (I⁻).

To balance the charges, lead would need to be in its +4 oxidation state to combine with four iodide ions. However, lead is more stable in its +2 oxidation state. This means that the compound PbI₂ (Lead(II) iodide) is the more likely and stable compound.