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  • Ionic Equation: Reaction of Iodide with Acidified Hydrogen Peroxide
    Here's the ionic equation for the reaction between aqueous iodide ions (I-) and acidified hydrogen peroxide (H₂O₂):

    Overall Reaction:

    2I⁻(aq) + H₂O₂(aq) + 2H⁺(aq) → I₂(aq) + 2H₂O(l)

    Ionic Equation:

    2I⁻(aq) + H₂O₂(aq) + 2H⁺(aq) → I₂(aq) + 2H₂O(l)

    Explanation:

    * Reactants:

    * Iodide ions (I⁻) are present in solution.

    * Hydrogen peroxide (H₂O₂) is dissolved in water.

    * Acidification provides hydrogen ions (H⁺).

    * Products:

    * Iodine (I₂) is formed and is slightly soluble in water, giving the solution a brown color.

    * Water (H₂O) is produced.

    * Key Points:

    * This is a redox reaction where iodide ions (I⁻) are oxidized to iodine (I₂) and hydrogen peroxide (H₂O₂) is reduced to water (H₂O).

    * The acidification is crucial because it provides the necessary hydrogen ions for the reaction to proceed.

    Important Note: The above reaction is a simplified representation. In reality, the reaction mechanism involves several intermediate steps and may be influenced by factors like concentration and temperature.

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