The reaction of boric acid (H₃BO₃) with sodium hydroxide (NaOH) is a neutralization reaction, producing sodium borate (Na₃BO₃) and water (H₂O).

Here's the balanced chemical equation:

H₃BO₃ (aq) + 3 NaOH (aq) → Na₃BO₃ (aq) + 3 H₂O (l)

Explanation:

* H₃BO₃ (aq): Boric acid in aqueous solution.

* NaOH (aq): Sodium hydroxide in aqueous solution.

* Na₃BO₃ (aq): Sodium borate in aqueous solution.

* H₂O (l): Water in liquid form.

Key Points:

* This reaction is exothermic, meaning it releases heat.

* Boric acid is a weak acid, while sodium hydroxide is a strong base.

* The reaction proceeds in a 1:3 molar ratio of boric acid to sodium hydroxide.

* The sodium borate formed is a salt.

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