Here's why:

* NaOH is a strong base and KI is a soluble salt.

* When they react in solution, they form sodium iodide (NaI) and potassium hydroxide (KOH), both of which are also soluble in water.

The reaction is:

NaOH(aq) + KI(aq) → NaI(aq) + KOH(aq)

Since all the products are soluble, they remain dissolved in the solution and no solid precipitate forms.