Here's how to calculate the liters of a 4 M lithium bromide (LiBr) solution you can make using 100 grams of LiBr:

1. Find the molar mass of LiBr:

* Li: 6.941 g/mol

* Br: 79.904 g/mol

* Molar mass of LiBr = 6.941 + 79.904 = 86.845 g/mol

2. Calculate the moles of LiBr:

* Moles = Mass / Molar Mass

* Moles = 100 g / 86.845 g/mol

* Moles ≈ 1.15 mol

3. Determine the volume of the 4 M solution:

* Molarity (M) = Moles / Volume (L)

* Volume (L) = Moles / Molarity

* Volume (L) = 1.15 mol / 4 mol/L

* Volume (L) ≈ 0.2875 L

Therefore, you can make approximately 0.2875 liters (or 287.5 milliliters) of a 4 M lithium bromide solution using 100 grams of LiBr.