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  • Copper(II) Sulfate + Iron Reaction: Products & Explanation
    Reacting copper(II) sulfate (CuSO₄) with iron (Fe) yields iron(II) sulfate (FeSO₄) and copper metal (Cu). This is a classic example of a single displacement reaction. Here's the balanced chemical equation:

    CuSO₄ (aq) + Fe (s) → FeSO₄ (aq) + Cu (s)

    Here's a breakdown of what happens:

    * Iron (Fe) is more reactive than copper (Cu). This means iron has a stronger tendency to lose electrons and form positive ions.

    * When iron is added to a solution of copper(II) sulfate, the iron atoms displace the copper ions from the solution.

    * The iron atoms lose electrons and become iron(II) ions (Fe²⁺), which then combine with the sulfate ions (SO₄²⁻) to form iron(II) sulfate (FeSO₄).

    * The copper ions (Cu²⁺) gain electrons and become copper metal (Cu), which precipitates out of the solution.

    You can observe this reaction visually:

    * The blue color of the copper(II) sulfate solution will fade as the reaction proceeds.

    * A reddish-brown deposit of copper metal will form on the surface of the iron.

    Important Note: The reaction rate can be increased by:

    * Using a more reactive form of iron, like iron filings or powdered iron.

    * Heating the solution.

    * Increasing the surface area of the iron.

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