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  • Preparing a 0.2N Sodium Chloride Solution: A Step-by-Step Guide
    Here's how to prepare a 0.2 N (Normal) sodium chloride (NaCl) solution:

    Understanding Normality

    * Normality (N) is a measure of concentration that expresses the number of gram equivalents of a solute per liter of solution.

    * Gram Equivalent is the mass of a substance that will react with or replace one mole of hydrogen ions (H+) in an acid-base reaction.

    * For NaCl: The gram equivalent weight is equal to the molecular weight because each NaCl molecule provides one mole of chloride ions (Cl-) that can react with one mole of H+ ions.

    Steps to Prepare a 0.2 N NaCl Solution

    1. Determine the Molecular Weight of NaCl: The molecular weight of NaCl is 58.44 g/mol.

    2. Calculate the Mass of NaCl Needed:

    * Since the gram equivalent weight of NaCl is equal to its molecular weight, 0.2 N NaCl solution contains 0.2 gram equivalents of NaCl per liter.

    * To make 1 liter of 0.2 N NaCl solution, you'll need:

    * 0.2 gram equivalents/liter * 58.44 g/equivalent = 11.688 g of NaCl

    3. Dissolve NaCl in Water:

    * Weigh out 11.688 g of NaCl.

    * Add it to a volumetric flask with a capacity slightly larger than 1 liter (e.g., a 1.2 L flask).

    * Add a small amount of distilled water (about half the flask volume) and stir gently until the NaCl dissolves completely.

    * Carefully add more distilled water until the solution reaches the 1-liter mark on the flask.

    * Stopper the flask and invert it several times to ensure thorough mixing.

    Important Considerations:

    * Water Quality: Use distilled or deionized water to avoid introducing impurities.

    * Accuracy: Use a balance with good accuracy to weigh the NaCl.

    * Volumetric Flask: Use a volumetric flask for accurate volume measurement.

    * Labeling: Label your solution clearly with the concentration (0.2 N NaCl), date of preparation, and any other relevant information.

    Example: Preparing 500 mL of 0.2 N NaCl

    * You would need half the amount of NaCl for a 500 mL solution (11.688 g / 2 = 5.844 g).

    * Follow the same dissolution steps, but use a 500 mL volumetric flask.

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