The reaction of 2-butene with potassium permanganate (KMnO4) depends on the reaction conditions. Here are the two main possibilities:

1. Cold, dilute KMnO4 (syn-dihydroxylation):

* Conditions: Cold, dilute solution of KMnO4 in water with a base like NaOH.

* Product: 2,3-butanediol (a vicinal diol)

* Equation:

CH3CH=CHCH3 + [O] + H2O → CH3CH(OH)CH(OH)CH3

Note: The [O] represents the oxidizing agent from KMnO4.

2. Hot, concentrated KMnO4 (oxidative cleavage):

* Conditions: Hot, concentrated solution of KMnO4 in water with a base like NaOH.

* Products: Acetic acid (CH3COOH) and Carbon dioxide (CO2)

* Equation:

CH3CH=CHCH3 + 4[O] + H2O → 2CH3COOH + CO2

Note: The [O] represents the oxidizing agent from KMnO4.

In summary:

* Cold, dilute KMnO4: 2-butene undergoes syn-dihydroxylation to form 2,3-butanediol.

* Hot, concentrated KMnO4: 2-butene undergoes oxidative cleavage to form acetic acid and carbon dioxide.