1. Write the balanced chemical equation:

The decomposition of hydrogen peroxide (H₂O₂) produces water (H₂O) and oxygen gas (O₂):

2 H₂O₂ → 2 H₂O + O₂

2. Calculate the moles of H₂O₂:

* Molarity (M) = moles of solute / liters of solution

* 0.500 M = moles of H₂O₂ / 0.050 L

* moles of H₂O₂ = 0.025 moles

3. Use stoichiometry to find moles of O₂:

* From the balanced equation, 2 moles of H₂O₂ produce 1 mole of O₂.

* moles of O₂ = (0.025 moles H₂O₂) * (1 mole O₂ / 2 moles H₂O₂) = 0.0125 moles O₂

4. Calculate the mass of O₂:

* Molar mass of O₂ = 32 g/mol

* mass of O₂ = (0.0125 moles O₂) * (32 g/mol) = 0.40 g

Therefore, 0.40 grams of O₂ will be produced.