Here's how to determine the net ionic equation for the reaction of aqueous potassium iodide (KI) with lead(II) nitrate (Pb(NO₃)₂):

1. Write the balanced molecular equation:

2KI(aq) + Pb(NO₃)₂(aq) → PbI₂(s) + 2KNO₃(aq)

2. Identify the spectator ions:

* Spectator ions are ions that appear on both sides of the equation and do not participate in the reaction.

* In this case, the spectator ions are K⁺ and NO₃⁻.

3. Write the net ionic equation:

* Net ionic equation: The equation that shows only the species that directly participate in the reaction.

* Remove the spectator ions from the balanced molecular equation.

The net ionic equation is:

Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s)