1. Determine the molar mass of FeNO₃₂:

* Fe (Iron): 55.845 g/mol

* N (Nitrogen): 14.007 g/mol

* O (Oxygen): 15.999 g/mol

Molar mass of FeNO₃₂ = 55.845 + 14.007 + (3 * 15.999) = 111.84 g/mol

2. Calculate the moles of FeNO₃₂:

Moles = mass / molar mass

Moles of FeNO₃₂ = 53.55 g / 111.84 g/mol = 0.478 mol

3. Determine the moles of nitrogen atoms:

Since there is one nitrogen atom per formula unit of FeNO₃₂, the moles of nitrogen atoms are equal to the moles of FeNO₃₂.

Therefore, there are 0.478 moles of nitrogen atoms present in 53.55 g of FeNO₃₂.