The combustion of any alkane, including 2-methyloctane and 3-ethyloctane, will produce the same products: carbon dioxide (CO2) and water (H2O).

Here's the balanced chemical equation for the combustion of 2-methyloctane:

C9H20 + 14O2 → 9CO2 + 10H2O

And for 3-ethyloctane:

C10H22 + 15.5O2 → 10CO2 + 11H2O

Key Points:

* Combustion is a chemical reaction between a substance and an oxidant, usually oxygen, that produces heat and light.

* Alkanes are hydrocarbons containing only single bonds between carbon atoms.

* In complete combustion, all carbon atoms are converted to CO2 and all hydrogen atoms to H2O.

While the specific number of moles of CO2 and H2O produced will vary depending on the molecular formula of the alkane, the products themselves will always be the same.