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  • Water Production from Oxygen and Ethylene: A Stoichiometry Calculation
    Here's how to solve this problem:

    1. Write the balanced chemical equation:

    C₂H₄ + 3O₂ → 2CO₂ + 2H₂O

    2. Determine the mole ratio:

    From the balanced equation, we see that 3 moles of oxygen (O₂) react to produce 2 moles of water (H₂O).

    3. Calculate the moles of water produced:

    * We have 2.16 mol of oxygen.

    * Using the mole ratio, we can set up a proportion:

    (2 mol H₂O / 3 mol O₂) = (x mol H₂O / 2.16 mol O₂)

    * Solving for x: x = (2 * 2.16) / 3 = 1.44 mol H₂O

    4. Convert moles of water to molecules:

    * Avogadro's number tells us there are 6.022 x 10²³ molecules in one mole.

    * Multiply the moles of water by Avogadro's number:

    1.44 mol H₂O * (6.022 x 10²³ molecules/mol) = 8.67 x 10²³ molecules of H₂O

    Therefore, 2.16 mol of oxygen can produce 8.67 x 10²³ molecules of water.

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