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  • Stoichiometry Problem: Calculating HCl Reactant with Zinc
    Here's how to solve this problem:

    1. Write the Balanced Chemical Equation:

    The reaction between zinc (Zn) and hydrochloric acid (HCl) produces zinc chloride (ZnCl₂) and hydrogen gas (H₂):

    Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)

    2. Determine the Limiting Reactant:

    * Moles of Zinc: You're given 1.80 mol of zinc.

    * Moles of Hydrochloric Acid: You need to convert 7.10 g of HCl to moles.

    * Molar mass of HCl = 1.01 g/mol (H) + 35.45 g/mol (Cl) = 36.46 g/mol

    * Moles of HCl = (7.10 g) / (36.46 g/mol) = 0.195 mol

    The limiting reactant is hydrochloric acid (HCl) because you have less of it in moles.

    3. Calculate the Mass of HCl Reacted:

    * Stoichiometry: The balanced equation tells us that 1 mole of Zn reacts with 2 moles of HCl.

    * Moles of HCl reacting: Since HCl is the limiting reactant, it will be completely consumed. Therefore, 0.195 mol of HCl will react.

    * Mass of HCl:

    * Mass of HCl = (0.195 mol) * (36.46 g/mol) = 7.10 g

    Answer: 7.10 grams of hydrochloric acid are reacted.

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