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  • Understanding the Polarity of C3H6Br2 (1,2-Dibromopropane)
    C3H6Br2 (1,2-dibromopropane) is polar. Here's why:

    * Molecular Geometry: The central carbon atom in 1,2-dibromopropane is bonded to two bromine atoms, one hydrogen atom, and a CH2 group. This results in a tetrahedral geometry around the central carbon.

    * Electronegativity Difference: Bromine (Br) is more electronegative than carbon (C) and hydrogen (H). This means that the bromine atoms pull electron density towards themselves, creating partial negative charges (δ-) on the bromine atoms and partial positive charges (δ+) on the carbon and hydrogen atoms.

    * Dipole Moment: The unequal sharing of electrons creates a dipole moment within each C-Br bond. Since the molecule is not symmetrical, these dipole moments do not cancel each other out. Instead, they combine to create a net dipole moment for the entire molecule.

    Therefore, the presence of a net dipole moment makes 1,2-dibromopropane a polar molecule.

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