* Identify the elements: The formula 4AgC₂H₃O₂ tells us the compound contains silver (Ag), carbon (C), hydrogen (H), and oxygen (O).

* Count the atoms in one molecule:

* 1 silver atom (Ag)

* 2 carbon atoms (C₂)

* 3 hydrogen atoms (H₃)

* 2 oxygen atoms (O₂)

* Total atoms in one molecule: 1 + 2 + 3 + 2 = 8 atoms

* Multiply by the coefficient: The coefficient "4" in front of the formula means there are 4 molecules. So, 8 atoms/molecule * 4 molecules = 32 atoms

Therefore, there are 32 atoms in 4AgC₂H₃O₂.