Here's how to calculate the atomic mass of AgBr (silver bromide):

1. Find the atomic masses of the elements:

* Ag (Silver): 107.8682 amu (atomic mass units)

* Br (Bromine): 79.904 amu

2. Add the atomic masses together:

* AgBr = 107.8682 amu + 79.904 amu = 187.7722 amu

Therefore, the atomic mass of AgBr is approximately 187.7722 amu.