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  • Reaction of Iron(II) Acetate and Sodium Phosphate: Products and Explanation
    The reaction between aqueous solutions of iron(II) acetate (Fe(C₂H₃O₂)₂) and sodium phosphate (Na₃PO₄) is a double displacement reaction that results in the formation of iron(II) phosphate (Fe₃(PO₄)₂) and sodium acetate (NaC₂H₃O₂) .

    Here's the balanced chemical equation:

    3Fe(C₂H₃O₂)₂(aq) + 2Na₃PO₄(aq) → Fe₃(PO₄)₂(s) + 6NaC₂H₃O₂(aq)

    Explanation:

    * Iron(II) phosphate (Fe₃(PO₄)₂) is a solid and precipitates out of the solution.

    * Sodium acetate (NaC₂H₃O₂) remains dissolved in the solution.

    Important Considerations:

    * Solubility: It's crucial to understand the solubility rules to predict the products. In this case, iron(II) phosphate is generally insoluble in water, while sodium acetate is soluble.

    * Balancing: The equation must be balanced to ensure the same number of atoms of each element on both sides of the equation.

    * State Symbols: (aq) indicates an aqueous solution (dissolved in water), and (s) indicates a solid precipitate.

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