1. Find the molar mass of LiOH:
* Li: 6.941 g/mol
* O: 15.999 g/mol
* H: 1.008 g/mol
Total molar mass of LiOH = 6.941 + 15.999 + 1.008 = 23.948 g/mol
2. Calculate the mass of oxygen in LiOH:
* Oxygen's molar mass is 15.999 g/mol.
3. Calculate the percent composition of oxygen:
(Mass of oxygen / Molar mass of LiOH) * 100%
= (15.999 g/mol / 23.948 g/mol) * 100%
= 66.81%
Therefore, the percent composition of oxygen in lithium hydroxide (LiOH) is 66.81%.
