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  • Lead(II) Carbonate and Nitric Acid Reaction: Chemical Equation & Explanation
    The reaction between lead(II) carbonate (PbCO₃) and nitric acid (HNO₃) is a classic acid-base reaction that produces a salt, water, and carbon dioxide gas. Here's the balanced chemical equation:

    PbCO₃(s) + 2 HNO₃(aq) → Pb(NO₃)₂(aq) + H₂O(l) + CO₂(g)

    Here's a breakdown of what happens:

    * Lead(II) carbonate (PbCO₃): This is a solid, white compound.

    * Nitric acid (HNO₃): This is a strong acid, meaning it readily donates protons (H+).

    * Lead(II) nitrate (Pb(NO₃)₂): This is a soluble salt formed in the reaction. It dissolves in water, producing lead(II) ions (Pb²⁺) and nitrate ions (NO₃⁻).

    * Water (H₂O): This is a liquid formed as a result of the reaction.

    * Carbon dioxide (CO₂): This is a gas produced as a result of the reaction. It is responsible for the fizzing you would observe.

    In simple terms:

    When lead(II) carbonate reacts with nitric acid, the acid breaks down the carbonate ion (CO₃²⁻) into carbon dioxide gas and water. The lead(II) ions then combine with the nitrate ions from the acid to form lead(II) nitrate.

    Observation:

    The reaction is readily apparent. You'll see fizzing as carbon dioxide gas is released. The solid lead(II) carbonate will dissolve as the reaction proceeds, and a colorless solution of lead(II) nitrate will be formed.

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