1. Determine the Electron Configuration
* Tellurium (Te) has an atomic number of 52, meaning it has 52 electrons.
* The electron configuration for tellurium is: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁴
2. Understand the Relationship Between l and Subshells
* The quantum number *l* represents the angular momentum of an electron and defines the shape of its orbital.
* *l* = 0 corresponds to an s orbital (spherical)
* *l* = 1 corresponds to a p orbital (dumbbell-shaped)
* *l* = 2 corresponds to a d orbital (more complex shape)
3. Identify the p Subshells
* In the electron configuration, the subshells with *l* = 1 are the p subshells: 2p, 3p, 4p, and 5p.
4. Count the Electrons in the p Subshells
* 2p: 6 electrons
* 3p: 6 electrons
* 4p: 6 electrons
* 5p: 4 electrons
5. Calculate the Total
* Add the electrons from all the p subshells: 6 + 6 + 6 + 4 = 22 electrons
Therefore, there are 22 electrons in a ground-state tellurium atom with an *l* value of 1.
