1. Write the unbalanced equation:

C + O₂ → CO₂

2. Balance the equation:

C + O₂ → CO₂ (This equation is already balanced)

3. Determine the limiting reactant:

* Moles of C: Assume we have 4 grams of carbon. The molar mass of carbon is 12.01 g/mol.

Moles of C = (4 g) / (12.01 g/mol) = 0.333 mol

* Moles of O₂: The molar mass of O₂ is 32.00 g/mol.

Moles of O₂ = (10.67 g) / (32.00 g/mol) = 0.333 mol

Since we have equal moles of both reactants, they are consumed completely, and there is no limiting reactant.

4. Calculate the moles of CO₂ produced:

From the balanced equation, we see that 1 mole of C reacts with 1 mole of O₂ to produce 1 mole of CO₂. Since we have 0.333 moles of both reactants, we will produce 0.333 moles of CO₂.

5. Calculate the mass of CO₂ produced:

The molar mass of CO₂ is 44.01 g/mol.

Mass of CO₂ = (0.333 mol) * (44.01 g/mol) = 14.65 g

Therefore, 14.65 grams of CO₂ are produced when 4 grams of C are added to 10.67 grams of O₂.