The product of sodium hydroxide (NaOH) and copper sulfate (CuSO₄) is a blue precipitate of copper hydroxide (Cu(OH)₂) and a solution of sodium sulfate (Na₂SO₄).

Here's the balanced chemical equation:

2NaOH(aq) + CuSO₄(aq) → Cu(OH)₂(s) + Na₂SO₄(aq)

Here's a breakdown of the reaction:

* Sodium hydroxide (NaOH) is a strong base.

* Copper sulfate (CuSO₄) is a soluble salt containing copper ions (Cu²⁺).

* When these two solutions are mixed, the hydroxide ions (OH⁻) from NaOH react with the copper ions (Cu²⁺) from CuSO₄.

* This reaction forms copper hydroxide (Cu(OH)₂) which is insoluble in water and precipitates out as a blue solid.

* The remaining ions, sodium (Na⁺) and sulfate (SO₄²⁻), remain in solution as sodium sulfate (Na₂SO₄).

This reaction is an example of a double displacement reaction where the cations and anions of two reactants switch places to form new products.