Here's how to write the balanced equation for the reaction between chromium(II) nitrate and sodium hydroxide:

1. Write the reactants and products:

* Chromium(II) nitrate: Cr(NO₃)₂

* Sodium hydroxide: NaOH

* Products: Chromium(II) hydroxide (Cr(OH)₂) and sodium nitrate (NaNO₃)

2. Write the unbalanced equation:

Cr(NO₃)₂ (aq) + NaOH (aq) → Cr(OH)₂ (s) + NaNO₃ (aq)

3. Balance the equation:

* Chromium (Cr): Already balanced (1 on each side)

* Nitrate (NO₃): 2 on the left, 1 on the right. Add a coefficient of 2 in front of NaNO₃.

* Sodium (Na): 1 on the left, 2 on the right. Add a coefficient of 2 in front of NaOH.

* Hydroxide (OH): 2 on the right, 2 on the left.

4. The balanced equation:

Cr(NO₃)₂ (aq) + 2 NaOH (aq) → Cr(OH)₂ (s) + 2 NaNO₃ (aq)