When you mix potassium iodide (KI) and lead nitrate (Pb(NO₃)₂) solutions, you get a yellow precipitate of lead iodide (PbI₂) . The remaining liquid is a solution of potassium nitrate (KNO₃).

Here's the reaction:

2 KI(aq) + Pb(NO₃)₂(aq) → PbI₂(s) + 2 KNO₃(aq)

Let me break down the reaction:

* KI (aq): Potassium iodide dissolved in water (aqueous solution)

* Pb(NO₃)₂ (aq): Lead nitrate dissolved in water (aqueous solution)

* PbI₂ (s): Lead iodide, a bright yellow solid (precipitate)

* KNO₃ (aq): Potassium nitrate dissolved in water (aqueous solution)

This reaction is a double displacement reaction where the positive and negative ions switch partners. The lead iodide forms an insoluble compound, causing it to precipitate out of the solution, leaving the potassium nitrate dissolved in the water.