1. Find Boron's Atomic Number:
* Boron has an atomic number of 5, meaning it has 5 protons and 5 electrons.
2. Identify the Previous Noble Gas:
* The previous noble gas on the periodic table is helium (He), which has an atomic number of 2.
3. Determine the Remaining Electrons:
* Boron has 5 electrons, and helium has 2 electrons. Subtract the number of electrons in helium from the number of electrons in boron: 5 - 2 = 3 electrons.
4. Write the Noble Gas Configuration:
* The noble gas configuration of boron is [He] 2s² 2p¹
Explanation:
* [He] represents the filled electron configuration of helium.
* 2s² indicates that the 2s subshell contains 2 electrons.
* 2p¹ indicates that the 2p subshell contains 1 electron.
