1. Find the molar mass of KOH:
* K (potassium): 39.10 g/mol
* O (oxygen): 16.00 g/mol
* H (hydrogen): 1.01 g/mol
* Total molar mass of KOH: 39.10 + 16.00 + 1.01 = 56.11 g/mol
2. Calculate the number of moles in 1 gram of KOH:
* Moles = mass / molar mass
* Moles = 1 g / 56.11 g/mol = 0.0178 mol
3. Calculate the number of molecules in 0.0178 mol of KOH:
* Use Avogadro's number: 6.022 x 10^23 molecules/mol
* Molecules = moles x Avogadro's number
* Molecules = 0.0178 mol x 6.022 x 10^23 molecules/mol = 1.07 x 10^22 molecules
4. Calculate the total number of atoms:
* Each molecule of KOH has 3 atoms (1 K, 1 O, 1 H).
* Total atoms = molecules x atoms per molecule
* Total atoms = 1.07 x 10^22 molecules x 3 atoms/molecule = 3.21 x 10^22 atoms
Therefore, there are approximately 3.21 x 10^22 atoms in 1 gram of KOH.
