1. Balanced Chemical Equation:

First, we need the balanced chemical equation for the reaction between aluminum and zinc chloride:

2 Al + 3 ZnCl₂ → 2 AlCl₃ + 3 Zn

2. Mole Ratio:

From the balanced equation, we see that 2 moles of AlCl₃ are produced for every 3 moles of ZnCl₂.

3. Calculate Moles of AlCl₃:

Use the mole ratio to find the moles of AlCl₃ needed:

(0.88 mol ZnCl₂) × (2 mol AlCl₃ / 3 mol ZnCl₂) = 0.587 mol AlCl₃

4. Convert Moles to Grams:

Use the molar mass of AlCl₃ (133.34 g/mol) to convert moles to grams:

(0.587 mol AlCl₃) × (133.34 g/mol) = 78.2 g AlCl₃

Therefore, it takes approximately 78.2 grams of aluminum chloride to make 0.88 mol of ZnCl₂.