1. Balanced Chemical Equation:
The balanced chemical equation for the reaction is:
Al₂S₃ + 6H₂O → 2Al(OH)₃ + 3H₂S
2. Mole Ratio:
From the balanced equation, we see that 1 mole of Al₂S₃ reacts to produce 3 moles of H₂S.
3. Theoretical Yield Calculation:
Since we have 4.0 moles of Al₂S₃, we can use the mole ratio to calculate the theoretical yield of H₂S:
(4.0 mol Al₂S₃) × (3 mol H₂S / 1 mol Al₂S₃) = 12 mol H₂S
Therefore, the theoretical yield of H₂S is 12 moles.
