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  • Copper(II) Hydroxide and Sodium Nitrate Reaction: Decomposition and Products
    When copper(II) hydroxide (Cu(OH)₂) and sodium nitrate (NaNO₃) are heated, the following reaction occurs:

    Cu(OH)₂(s) + 2NaNO₃(s) → Cu(NO₃)₂(s) + 2NaOH(s)

    Here's a breakdown of what happens:

    * Decomposition of copper(II) hydroxide: When heated, copper(II) hydroxide decomposes to form copper(II) oxide (CuO) and water (H₂O):

    Cu(OH)₂(s) → CuO(s) + H₂O(g)

    * Reaction with sodium nitrate: The sodium nitrate will react with the copper(II) oxide to form copper(II) nitrate (Cu(NO₃)₂) and sodium hydroxide (NaOH):

    CuO(s) + 2NaNO₃(s) → Cu(NO₃)₂(s) + 2NaOH(s)

    Overall Reaction:

    The overall reaction can be represented as the combination of the above steps:

    Cu(OH)₂(s) + 2NaNO₃(s) → Cu(NO₃)₂(s) + 2NaOH(s)

    Important Notes:

    * This reaction is an example of a double displacement reaction.

    * The reaction is not very vigorous and will likely proceed slowly.

    * The products, copper(II) nitrate and sodium hydroxide, are both soluble in water.

    * The water produced in the decomposition of copper(II) hydroxide will evaporate, leaving behind the solid products.

    Safety Precautions:

    * Copper(II) hydroxide is a mild irritant.

    * Sodium nitrate is a strong oxidizer.

    * Always wear appropriate safety gear, such as gloves and eye protection, when handling chemicals.

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