* Identify the elements and their atomic weights:
* Silver (Ag): 107.87 g/mol
* Nitrogen (N): 14.01 g/mol
* Oxygen (O): 16.00 g/mol
* Determine the number of atoms of each element in the formula:
* Ag: 1 atom
* N: 1 atom
* O: 3 atoms
* Multiply the atomic weight of each element by its number of atoms:
* Ag: 107.87 g/mol * 1 = 107.87 g/mol
* N: 14.01 g/mol * 1 = 14.01 g/mol
* O: 16.00 g/mol * 3 = 48.00 g/mol
* Add the results to find the molecular weight:
* 107.87 g/mol + 14.01 g/mol + 48.00 g/mol = 169.88 g/mol
Therefore, the molecular weight of silver nitrate (AgNO₃) is 169.88 g/mol.
