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  • Sodium-Sulfur Ionic Bond Formation: Understanding the Ratio
    You need two sodium atoms to form an ionic bond with one sulfur atom. Here's why:

    * Sodium (Na) has one valence electron (electron in its outermost shell). It wants to lose this electron to achieve a stable octet (8 electrons) like the noble gases.

    * Sulfur (S) has six valence electrons. It wants to gain two electrons to achieve a stable octet.

    Therefore, two sodium atoms each lose one electron, giving a total of two electrons that are transferred to the sulfur atom. This results in:

    * Two sodium ions (Na+)

    * One sulfide ion (S2-)

    The opposite charges then attract each other, forming the ionic compound sodium sulfide (Na₂S).

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