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  • Chlorine vs. Iodine Boiling Points: Understanding Intermolecular Forces
    You would expect the boiling point of chlorine to be lower than that of iodine. Here's why:

    * Intermolecular Forces: The strength of intermolecular forces (the forces between molecules) plays a crucial role in determining boiling point. Stronger intermolecular forces require more energy to overcome, leading to higher boiling points.

    * London Dispersion Forces: The primary intermolecular force between chlorine (Cl₂) and iodine (I₂) molecules is London Dispersion Forces. These forces arise from temporary fluctuations in electron distribution around the molecules, creating temporary dipoles that induce dipoles in neighboring molecules.

    * Size and Polarizability: Iodine is a much larger atom than chlorine. Larger atoms have more electrons and a larger electron cloud, making them more polarizable (easier to induce a temporary dipole). This means iodine molecules experience stronger London Dispersion Forces compared to chlorine molecules.

    * Boiling Point Trend: As you move down the halogen group (F, Cl, Br, I), atomic size increases, and the strength of London Dispersion Forces increases. This leads to a trend of increasing boiling points as you go down the group.

    In summary: Iodine has stronger London Dispersion Forces due to its larger size and higher polarizability, resulting in a higher boiling point compared to chlorine.

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