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  • Calculate the Empirical Formula: Magnesium and Bromine Compound
    Here's how to find the empirical formula for a compound containing 13% magnesium (Mg) and 87% bromine (Br):

    1. Assume a 100g Sample

    * This makes the calculations easier. We'll have 13g of Mg and 87g of Br.

    2. Convert Grams to Moles

    * Divide the mass of each element by its molar mass:

    * Mg: 13g / 24.31 g/mol = 0.53 mol

    * Br: 87g / 79.90 g/mol = 1.09 mol

    3. Find the Mole Ratio

    * Divide each mole value by the smallest mole value (in this case, 0.53 mol):

    * Mg: 0.53 mol / 0.53 mol = 1

    * Br: 1.09 mol / 0.53 mol = 2.06 (approximately 2)

    4. Write the Empirical Formula

    * The mole ratio tells you the simplest whole-number ratio of atoms in the compound.

    * The empirical formula is MgBr₂

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