1. Balanced Chemical Equation

The reaction you're describing is the combustion of carbon monoxide:

2 CO (g) + O₂ (g) → 2 CO₂ (g)

2. Stoichiometry

The balanced equation tells us that 2 moles of CO react to produce 2 moles of CO₂. This means the mole ratio of CO to CO₂ is 1:1.

3. Ideal Gas Law

At STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 L. We can use this information to convert between volume and moles.

4. Calculation

* Convert mL to L: 541 mL CO₂ = 0.541 L CO₂

* Calculate moles of CO₂:

* (0.541 L CO₂) / (22.4 L/mol) = 0.0241 mol CO₂

* Since the mole ratio is 1:1, you need 0.0241 moles of CO.

* Calculate the volume of CO at STP:

* (0.0241 mol CO) * (22.4 L/mol) = 0.540 L CO

* Convert L to mL: 0.540 L CO = 540 mL CO

Therefore, you need 540 mL of carbon monoxide at STP to produce 541 mL of carbon dioxide.