1. Find the molar mass of AlCl₃:
* Aluminum (Al) has a molar mass of 26.98 g/mol
* Chlorine (Cl) has a molar mass of 35.45 g/mol
* AlCl₃ has one aluminum atom and three chlorine atoms, so its molar mass is: 26.98 g/mol + (3 * 35.45 g/mol) = 133.33 g/mol
2. Use the formula:
* moles = mass / molar mass
3. Plug in the values:
* moles = 4177 g / 133.33 g/mol
* moles ≈ 31.33 mol
Therefore, there are approximately 31.33 moles in 4177 g of aluminum chloride.
