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  • Calculating the Mass of HBr Gas Produced from H₂ and Br₂ Reaction
    Here's how to solve this problem:

    1. Balanced Chemical Equation:

    The balanced chemical equation for the reaction is:

    H₂(g) + Br₂(g) → 2HBr(g)

    2. Mole Ratio:

    The equation shows that 1 mole of Br₂ reacts to produce 2 moles of HBr.

    3. Moles of HBr Produced:

    Since we have 1.25 moles of Br₂, and the mole ratio is 1:2, we'll produce twice as many moles of HBr:

    1.25 moles Br₂ * (2 moles HBr / 1 mole Br₂) = 2.50 moles HBr

    4. Molar Mass of HBr:

    The molar mass of HBr is:

    * 1.01 g/mol (H) + 79.90 g/mol (Br) = 80.91 g/mol

    5. Mass of HBr:

    To find the mass of HBr, multiply the moles of HBr by its molar mass:

    2.50 moles HBr * 80.91 g/mol = 202.28 g HBr

    Therefore, the mass of HBr gas produced is 202.28 grams.

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