1. Find the molar mass of BH3

* Boron (B) has a molar mass of 10.81 g/mol

* Hydrogen (H) has a molar mass of 1.01 g/mol

* Molar mass of BH3 = 10.81 + (3 * 1.01) = 13.84 g/mol

2. Convert grams of BH3 to moles

* Moles = (grams) / (molar mass)

* Moles = 14.32 g / 13.84 g/mol = 1.034 mol

3. Convert moles to molecules

* Avogadro's number = 6.022 x 10^23 molecules/mol

* Molecules = (moles) * (Avogadro's number)

* Molecules = 1.034 mol * 6.022 x 10^23 molecules/mol = 6.23 x 10^23 molecules

Therefore, there are approximately 6.23 x 10^23 molecules of BH3 in 14.32 grams of BH3.