1. Write the balanced chemical equation:

CH₄ + 2O₂ → CO₂ + 2H₂O

2. Convert grams of methane to moles:

* Molar mass of CH₄ = 12.01 g/mol (C) + 4 * 1.01 g/mol (H) = 16.05 g/mol

* Moles of CH₄ = 16 g / 16.05 g/mol = 0.997 moles

3. Use the mole ratio from the balanced equation:

* The balanced equation shows that 1 mole of CH₄ produces 2 moles of H₂O.

4. Calculate moles of water produced:

* Moles of H₂O = 0.997 moles CH₄ * (2 moles H₂O / 1 mole CH₄) = 1.994 moles H₂O

Therefore, approximately 1.994 moles of water (H₂O) are produced from the reaction of 16 grams of methane (CH₄) with an unlimited supply of oxygen (O₂).